​The quadratic equation kx^2+(k-3)x+1=0 has two equal real roots. Find the possible values of k.

User Generated

FAF107837113036522011797

Mathematics

Description

The quadratic equation kx^2+(k-3)x+1=0 has two equal real roots. Find the possible values of k.

User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.

Explanation & Answer

Thank you for the opportunity to help you with your question!

This is how you find roots in quadratic equation 

(-b+- sqrt(b^2-4ac))/2a

 if the roots are equal that means b^2-4ac=0

so

(k-3)^2-4k=0

k^2-6k+9-4k=0

k^2-10k+9=0

=> k=5+-sqrt(25-9) so k=9 or k=1


Please let me know if you need any clarification. I'm always happy to answer your questions.


Anonymous
I was struggling with this subject, and this helped me a ton!

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4

Related Tags