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Man has invested $205000 in three properties. The question is quite incomplete. Pease reply to me that the man has invested $205000 in each company or $205000 equally distributed in three companies.

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A man has $205,000 invested in three properties. One earns 12%, one 10% and one 8%. His annual income from the properties is $19,700 and the amount invested at 8% is twice that invested at 12%.

Now It seems to be a complete question. See , man has invested $205000 in three properties. Let tge common multiple be x. So when he invests $ x in the property at 12% Then amount Invested at 8% is $ 2x. So remain amount = $205000- (2x+x)= $205000-3x that he invests in 10% . Now income from 12% rate = 12x/100 $ . Income from 8% rate = 16x/200$. Income from 10% = 205000-3x/10 $. Now total annual income = 12x/100+16x/100+(205000-3x)/10 = 19700 or (12x+16x+2050000-30x)/100 =19700 or -28x+2050000 = 1970000 or 28x=2050000-1970000 or 28x=80000 or x= 80000/28 or x=20000/7. Now you can calculate the value of each property earnings by putting value of x. Any questions ask