Sue has $1.90 in dimes and nickels. If she has 10 more dimes than nickels, how many of each coin does she have?
Thank you for the opportunity to help you with your question! Hope your day is going well!
This is an algebra problem. Let's write down what we know.
Let's call x=nickels and y= dimes.
We know that in total, we have 1.90 dollars worth of nickles and dimes.
nickles are worth .05 and dimes are worth .10
.05x+.10y=1.90 (equation 1)
We know she has 10 more dimes than nickles.
Thus, we substitute y=x+10 into equation 1, and solve for x
Thus she has 6 nickles.
To find how many dimes we have, we substitute it into y=x+10
Thus she has 16 dimes and 6 nickles.
CHECK your work
Thus we have the correct answer!
16 dimes and 6 nickles.
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?