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Sue has \$1.90 in dimes and nickels. If she has 10 more dimes than nickels, how many of each coin does she have?

Sep 29th, 2015

Thank you for the opportunity to help you with your question! Hope your day is going well!

This is an algebra problem. Let's write down what we know.

Let's call x=nickels and y= dimes.

We know that in total, we have 1.90 dollars worth of nickles and dimes.

nickles are worth .05 and dimes are worth .10

.05x+.10y=1.90 (equation 1)

We know she has 10 more dimes than nickles.

Thus y=x+10

Thus, we substitute y=x+10 into equation 1, and solve for x

.05x+.10(x+10)=1.90

.05x+.10x+1=1.90

.15x+1=1.90

.15x=.90

x=6.

Thus she has 6 nickles.

To find how many dimes we have, we substitute it into y=x+10

y=6+10=16.

Thus she has 16 dimes and 6 nickles.

CHECK your work

16*.10+6 *.05=1.6+.3=1.9

Thus we have the correct answer!

16 dimes and 6 nickles.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 29th, 2015

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Sep 29th, 2015
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Sep 29th, 2015
May 24th, 2017
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