Cyanuric acid has the Formula C3H3N3O3. How may moles of this substance are in 325 mg samples of this substance? How many moles of Hydrogen are in the same sample?
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First we must get the molecular formula of cyanuric acid.
C=12, H=1, N=14, O=16
Therefore, we combine these atomic masses and get
Then we convert 325 mg to grams: 0.325 g
Divide the given mass by the molecular mass
0.325 g / 129 g/mol = 0.00252 mol cyanuric acid.
There are 3 mol H per every mol cyanuric acid. Therefore
0.00252 mol cyanuric acid * 3 mol H = 0.00756 mol H
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