Chem Question help please?

Chemistry
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Cyanuric acid has the Formula C3H3N3O3. How may moles of this substance are in 325 mg samples of this substance? How many moles of Hydrogen are in the same sample?

Sep 29th, 2015

Thank you for the opportunity to help you with your question!

First we must get the molecular formula of cyanuric acid. 

C=12, H=1, N=14, O=16

Therefore, we combine these atomic masses and get

(3*12)+(3*1)+(3*14)+(3*16)=129

Then we convert 325 mg to grams: 0.325 g

Divide the given mass by the molecular mass

0.325 g / 129 g/mol = 0.00252 mol cyanuric acid.

There are 3 mol H per every mol cyanuric acid. Therefore

0.00252 mol cyanuric acid * 3 mol H = 0.00756 mol H

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 29th, 2015

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Sep 29th, 2015
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