The length of a rectangular piece of steel in a bridge is 3 meters less than double the width. The perimeter of the piece of steel is 42 meters. Find the length of the piece of steel. Find the width of the piece of steel.

Thank you for the opportunity to help you with your question!

Let the length = L

Let the width = W

Now

length of a rectangular piece of steel in a bridge is 3 meters less than double the width

Meaning

L=2W-3

Perimeter = 2(Length + width)

=2(2W-3+W)

24 =2(3W-3)

or

6W-6=24

6W=30

W=30

Width is 30 meters

Length = 2*30-3 = 60-3 = 57 meters.

The question is asking for a length and width only. The answer in back of the book came up with the following answer:

L=13 meters

W=8 meters

I'm having problems figuring out how to write the equation...

I tried

x+x-3=42

2x-3=42

2x+45

x=22.5

and lost it from there....

Sorry my mistake, i used perimeter to be 24 meters instead of 42 meters. It is now correct here.

42 =2(3W-3)

6W-6=42

6W=48

W=8

Width is 8 meters

L=2*8-3 = 16-3=13

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