assume that the duration od human pregnancies can be described by a normal model with a mean 266 days and standard deviation 16 days.

Thank you for the opportunity to help you with your question!

First transform x=260 to z-score: z=(260-266)/16=- 6/16= -.375

P(z<.375)= .3538

This is still a little confusing the final answer that im trying to get is 0.002 but im unsure how to get there

sorry,I missed the negative sign of z but the final answer is the same.

In order to get a prob. of .002, z must be equal to -2.87. I have no idea why it should be .002

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