"nitrogen gas can be produced by reacting Na3N with chlorine gas. If the reaction was carried out at STP with 34.8 g of Na3N, what volume of nitrogen gas can be produced? " also "2 Na3N +3 Cl2 ---> 6 NaCl + N2 "
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Moles of Na3N reacting= Mass/molar mass=34.8/83=0.419mol
Moles of N2 produced=(1/2)*Moles of Na3N from reaction stoichiometry.
=(1/2)*0.419=0.2095 molVolume of N2=No of moles*Molar volume of ideal gas at STP
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