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Chemistry
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The minimum human daily nutritional requirement of the amino acid isoleucine C6H13NO2, has been reported to be 31.0mg amino acid/kg of body mass. If a person takes in 7.75x10^21 atoms of isoleucine, how many moles were ingested? How many mg were ingested?If the person weighs 147.4lbs, has the minimum daily requirement been met? Recall that 1lb=453.6g

Sep 30th, 2015

Thank you for the opportunity to help you with your question!

Number of moles = 7.75x10^21/6.02*10^23 = 0.013 moles.

Molar mass of isoleucine is 131g/mole

Mass of isoleucine were ingested: m = 131g/mole * 0.013 moles = 1.703g = 1703mg.

Person's weight in kg is: 147.4lbs*453.6g = 66.86kg.

Mass of isoleucine person takes: 1703mg/66.86kg = 25.47mg/kg.

So, the person does not take the minimum daily requirements of isoleucine.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 30th, 2015

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