Need explanation and help please!

label Chemistry
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

The minimum human daily nutritional requirement of the amino acid isoleucine C6H13NO2, has been reported to be 31.0mg amino acid/kg of body mass. If a person takes in 7.75x10^21 atoms of isoleucine, how many moles were ingested? How many mg were ingested?If the person weighs 147.4lbs, has the minimum daily requirement been met? Recall that 1lb=453.6g

Sep 30th, 2015

Thank you for the opportunity to help you with your question!

Number of moles = 7.75x10^21/6.02*10^23 = 0.013 moles.

Molar mass of isoleucine is 131g/mole

Mass of isoleucine were ingested: m = 131g/mole * 0.013 moles = 1.703g = 1703mg.

Person's weight in kg is: 147.4lbs*453.6g = 66.86kg.

Mass of isoleucine person takes: 1703mg/66.86kg = 25.47mg/kg.

So, the person does not take the minimum daily requirements of isoleucine.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 30th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Sep 30th, 2015
...
Sep 30th, 2015
Jun 23rd, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer