I am in transitional math and I am doing an algebra problem and I am not sure I know how to solve it. 4y-2(y-2)+3

Thank you for the opportunity to help you with your question!

ok i will help you just should you write the eqution on the right form ok :

if the equation is :

4y-2(y-2)+3 = 0

4y - 2y + 4 + 3 = 0

2y + 7 = 0

2y = -7

y = -7/2

if you don't understand please just ask

i am glad to work with you just invite me

Good luck

The correct answer according to the mymathlab is 2y+7 not 2y-7

ahh so is not an equation is factoring

so the answer is :

4y-2(y-2)+3 = 4y - 2y + 4 + 3 = 2y + 7

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