prove that any odd number is either of the form 4k+1 or of the from 4k+3, k belongs to Z
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Let m in Z be odd.
Using division algorithm, there exits unique p and t in Z such that
m=4p+t and 0<=t<=4
Therefore 4p is even, meaning t is not equal to zero and t is not equal to 2.
m=4p or m=4p+2 which are both even.
Therefore we conclude that
m=4p+1 and m=4p+3 are odd.
I dont understand why t can't be equal to 0 or 2.
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