Can't solve this probability tree?

label Mathematics
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schedule 1 Day
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Oct 2nd, 2015

Thank you for the opportunity to help you with your question!

In the box 11 balls

3 red, 4 blue and 4 yellow

probability of drawing yellow ball on second picking

(4/11) x (4/11) = 16/121 .....on first and second drawing of yellow ball only

(3/11) x (4/10) = 6/55........drawing a red ball followed by yellow one ( without replacement)

(4/11) x(4/10) = 8/55..........first pick being a blue ball followed by a yellow ball

1. overall probability of that the second ball drawn is yellow

16/121 + 6/55 + 8/55=234/605

probability of picking red ball on second drawing

(3/11) x (2/10) = 3/55

(4/11) x (3/10) = 6/55

(4/11) x (3/11) =12/121.....................here we replaced because the first pick was yellow!

2. 3/55 + 6/55 + 12/121 =159/605.............

hope that helps you, feel free to top up any point you ain't getting!


Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 2nd, 2015

Thank you!!!

Oct 2nd, 2015

Thank you!!!

Oct 2nd, 2015

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