# Find the amplitude and phase constant of the resulting oscillations.

label Physics
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A mass 1.2 kg is attached to a spring  on a friction-less air track. the mass is resting in equilibrium. A 10-gram bullet is fired into the mass to initiate oscillatory motion. The bullet hits mass from the left @ 120 m/s at t=0 and gets lodged inside of it. Period 15 seconds.

Bullet KE 72J   After bullet strike KE 0.595J Initiall Velocity 0.992 m/s

Find the amp and phase constant of the resulting oscillations. then write an explcit exp for position xt and velocity vt of the mass as a func of time

Oct 2nd, 2015

Initial Momentum = m x v = 0.010 * 120 = 1.2
Final momentum = Initial momentum = m x v
v = Initial momentum / m = 1.2 / (1.2 + 0.010) = 0.992 m/s

Bullet Kinetic energy  = 1/2 * m * v^2

Bullet kinetic energy = 1/2 * 0.010 * 120^2

Bullet kinetic energy = 72 J

Mass after bullet strick: Ek = 1/2 * mtotal * v^2

= 1/2 * 1.21 * 0.992^2 =

Mass after bullet strick  = 0.595 J

Oct 2nd, 2015

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Oct 2nd, 2015
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Oct 2nd, 2015
Nov 20th, 2017
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