While passing a slower car on the highway

label Physics
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schedule 1 Day
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While passing a slower car on the highway, you accelerate uniformly from 
14.0 m/s
 to 
27.0 m/s
 in a time of 10.4 s.

(a) How far do you travel during this time?

(b) What is your acceleration magnitude?

Oct 2nd, 2015

Thank you for the opportunity to help you with your question!


(a) distance = change in velocity x time = (27 -14)m/s * 10.4 s = 13 m/s * 10.4 s = 135.2 m

(b) a=(v2-v1)/t=(27-14)m/s/10.4s=13m/s/10.4s=1.25 m/s^2

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 2nd, 2015

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Oct 2nd, 2015
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