physics speed problem HELP!

label Physics
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Orville walks 400 m due east. He then continues to walk in a straight line either parallel or perpendicular to his initial displacement and stops 560 m northeast of his starting point. How far did he walk during the second portion of the trip and in which direction?

Answer: The second part of the trip was  m in the  direction.

Oct 2nd, 2015

Thank you for the opportunity to help you with your question!

Use Pythagoras theorem

The trip forms a triangle with

base  = b =400m

hypotenuse = hyp = 560 m

h = ?

hyp^2=b^2 + h^2

h^2=hyp^2 - b^2

h = square-root (hyp^2 - b^2)=square-root(560^2-400^2)=square-root(313600-160000)=square-root(153600)

h=392 m north

The second part of the trip was 392 m north

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 2nd, 2015

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