mathematics problems

label Mathematics
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schedule 1 Day
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1.       In five rolls of a standard die, what is the probability of rolling a “full house”, that is, two of one number and three of a different number.

Oct 2nd, 2015

Thank you for the opportunity to help you with your question!

There are 6 ways to choose the rank of the three of a kind, and then 5 ways to choose the rank of the pair. For 5 dies, there are 5! permutations and 6^5 possible outcomes. Hence, the probability of rolling a “full house” is:

6*5*5!/6^5

** P/S: Please remember to give me a review later on once the answer is correct. I would be highly appreciate it. Thank you. **
Oct 2nd, 2015

Hi

According to your answer it is 25/54 but the answer here says it is 25/648.. did i calculate wrong

thnx

Oct 2nd, 2015

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Oct 2nd, 2015
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Oct 2nd, 2015
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