During a baseball game, a batter hits a high
pop-up.
If the ball remains in the air for 5.1 s, how
high does it rise? The acceleration of gravity
is 9.8 m/s
2
.
Answer in units of m.

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The height of the ball at time t is

h(t) = h(0) + v(0)t - (1/2)gt²

Since the initial height of the ball, h(0), is not given, we have to assume that the height of the ball at t = 5.38 seconds is equal to its initial height.