During a baseball game, a batter hits a high pop-up. If the ball remains in the

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During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 5.1 s, how high does it rise? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.

Oct 4th, 2015

Thank you for the opportunity to help you with your question!

The total time of flight is 5.1 sec

Since the time required to go up and come downnis the same.

So the time to ccome down will be: .= 5.1/ 2 =2.55 sec

Now welhen the ball reaches the top position it stops there and its velocity becomes 0m/s


So , now applying the kinematifs eqn.

S = u*t + 0.5 * a *t^2

Here u = 0m/s

T= 2.55 sec

And a = g= 9.8m/s^2


So S = 31.86 m

Please let me know if you need any clarification for the doubts. I'm always happy to answer your questions. Looking forward to help you again. thank you. :)
Oct 4th, 2015

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