During a baseball game, a batter hits a high
If the ball remains in the air for 5.1 s, how
high does it rise? The acceleration of gravity
is 9.8 m/s
Answer in units of m.
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The total time of flight is 5.1 sec
Since the time required to go up and come downnis the same.
So the time to ccome down will be: .= 5.1/ 2 =2.55 sec
Now welhen the ball reaches the top position it stops there and its velocity becomes 0m/s
So , now applying the kinematifs eqn.
S = u*t + 0.5 * a *t^2
Here u = 0m/s
T= 2.55 sec
And a = g= 9.8m/s^2
So S = 31.86 m
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