Physics 2 Lab Simple Harmonic Motion-hooke’s Law Data & Calculations Report

Anonymous
timer Asked: Mar 25th, 2019
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Question Description

experiment 3: Simple Harmonic Motion-Hooke’s Law

I need answers for the attached lab questions/experiment questions, calculation, and graphs.

Tutor Answer

Geontiry
School: UC Berkeley

Hello buddy! I have attached the answer in a word document for you. Also, there is an outline. :) Let me know if you have any edits or have any questions.

Last Name 1

Name
Instructor's name
Course
Date
Laboratory Report
Part 1: Data and Calculations Table 1 Hooke’s Law
Is 𝑦0 = 0? If not 𝑦0 = 15.3 𝑐𝑚 = 0.153 𝑚
Mass m (g)

m (kg)

F=mg (N)

y (cm)

y (m)

50

0.05

0.4905

28.3

0.283

70

0.07

0.6867

34.7

0.347

90

0.09

0.8829

40.8

0.408

110

0.11

1.0791

46.5

0.465

130

0.13

1.2753

52.8

0.528

i)

The graph of force against displacement is as shown below:

Last Name 2

A Graph of Force Against Dispacement
1.4
∆𝐹

1.2

0.8−0.44

𝑠𝑙𝑜𝑝𝑒 = ∆𝑦 = 0.36−0.2 =2.25 N/m

Force, F (N)

1
0.8

∆𝐹

0.6
0.4

∆𝑦

0.2
0
0

0.1

0.2

0.3

0.4

0.5

0.6

Displacement, y(m)

ii)

The best line of fit is drawn and its slope calculated as shown:
𝑆𝑙𝑜𝑝𝑒 = 2.25 𝑁/𝑚

Thus, 𝑆𝑙𝑜𝑝𝑒 = 𝐾 = 2.25 𝑁/𝑚. This is because the slope from the graph of F vs y gives the
constant k as p...

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Anonymous
awesome work thanks

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