A car traveling at a constant speed of 36.4 km/hr passes a trooper hidden behind a billboard. One second after the speeding car passes the billboard, the trooper sets in a chase after the car with a constant acceleration of 3.96
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the car's speed is 36.4 * 5/18 = 10.11 m/s
the troop chases with an initial velocity u = 0
and acceleration = 3.96m/s^2
After a time t sec
the distance covered by the car = 10. 11 * t
and by the trooper = 0.5* a*t^2
for a successful chase, both the distances need to be equal:
so on solving we get t= 5.1 se
so the trooper over takes at 5.1
just a minute.
sorry there was some calculation mistake:
the distance covered by the car = 10. 11 * (t+1)
0.5* a*t^2 - 10. 11 * t - 10. 11= 0
on solving for t , we get t = 11.92 secso the chase will be complete at (11.92+ 1) = 12.92 sec
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