Thank you for the opportunity to help you with your question!
total points = 52
total ribbons = 24
1st place ribbons = 6
1st place points = 30
let the no. of second place ribbons be x.
so points = 3x
and the no. of third place ribbons = (24 - 5- x) = (19-x)
so points = (19-x)
now total points = 30 + 3x + (19-x) = 53
on solving we get x= 2
so the no. of 3rd [lace ribbons were 19- 2 = 17
I still don't get how to find the amount third place ribbons. Could you please explain this more?
the no of third place ribbons are : ( 24 - 5 - x)
and each ribbon gas one point so the no.of points = (19-x)
on putting this in the equation: 30 + 3x + (19-x) = 53
so x = 2
So the no of third place ribbons = 17
Wouldn't it be 18-x because 24 ribbons minus the 6 first place ribbons would be 18. Also, wouldn't it be 52 total because there were only 52 points?
oh sorry . yes it will be 18 -x
so points = (18-x)
now total points = 30 + 3x + (18-x) = 52
so the no. of 3rd [lace ribbons were 18- 2 = 16.
let me know if you need any clarification for the doubts. I'm always
happy to answer your questions. Looking forward to help you again. thank
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