##### Help me solve this algebraic word problem

 Mathematics Tutor: None Selected Time limit: 1 Day

Oct 4th, 2015

total points = 52

total ribbons = 24

1st place ribbons = 6

1st place points = 30

let the no. of second place ribbons be x.

so points = 3x

and the no. of third place ribbons = (24 - 5- x) = (19-x)

so  points = (19-x)

now total points = 30 + 3x + (19-x) = 53

on solving we get x= 2

so the no. of 3rd [lace ribbons were 19- 2 = 17

Please let me know if you need any clarification for the doubts. I'm always happy to answer your questions. Looking forward to help you again. thank you. :)
Oct 4th, 2015

I still don't get how to find the amount third place ribbons. Could you please explain this more?

Oct 4th, 2015

the no of third place  ribbons are : ( 24 - 5 - x)

and each ribbon gas one point so the no.of points =  (19-x)

on putting this in the equation: 30 + 3x + (19-x) = 53

so x = 2

So the no of third place ribbons = 17

Oct 4th, 2015

Wouldn't it be 18-x because 24 ribbons minus the 6 first place ribbons would be 18. Also, wouldn't it be 52 total because there were only 52 points?

Oct 4th, 2015

oh sorry . yes it will be 18 -x

so  points = (18-x)

now total points = 30 + 3x + (18-x) = 52

on solving we get x= 2

so the no. of 3rd [lace ribbons were 18- 2 = 16.

Please let me know if you need any clarification for the doubts. I'm always happy to answer your questions. Looking forward to help you again. thank you. :)

Oct 4th, 2015

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Oct 4th, 2015
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Oct 4th, 2015
Dec 10th, 2016
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