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the amount of carbon in the hydrocarbon = ( 12 / 44 ) * 1. 250 = 0.341 g
the amount of hydrogen in the hydrocarbon = ( 2/18 ) * 0.650 = 0.0723 g
so the amount of oxygen in the hydrocarbon is ( 1.550 - 0.341 - 0.0723) = 1.1367
the no. of hydrogen atoms = 0.0723/ 1 = 0.0723
the no. of carbon atoms = 0.341/12 = 0.028
the no. of oxygen atoms = 1.1367/16 = 0.07
now dividing each by the smallest no. we get the
the no. of hydrogen atoms = 0.0723/0.07 = 1
the no. of carbon atoms = 0.341/12 = 0.028 / 0.07 = 4
the no. of oxygen atoms = 1.1367/16 = 0.07/ 0.07 = 1
so the empirical formula is C4 H O
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