##### Emperical formula problem

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Oct 4th, 2015

Please let me know if you need any clarification for the doubts. I'm always happy to answer your questions. Looking forward to help you again. thank you. :)
Oct 4th, 2015

the amount of carbon in the hydrocarbon = ( 12 / 44 ) * 1. 250 = 0.341 g

the amount of hydrogen in the hydrocarbon = ( 2/18 ) * 0.650 = 0.0723 g

so the amount of oxygen in the hydrocarbon is ( 1.550 - 0.341 - 0.0723) = 1.1367

the no. of hydrogen atoms = 0.0723/ 1 = 0.0723

the no. of carbon atoms =  0.341/12 = 0.028

the  no. of oxygen atoms = 1.1367/16 = 0.07

now dividing each by the  smallest no. we get the

the no. of hydrogen atoms = 0.0723/0.07 = 1

the no. of carbon atoms =  0.341/12 = 0.028 / 0.07 = 4

the  no. of oxygen atoms = 1.1367/16 = 0.07/ 0.07 = 1

so the empirical formula is C4 H O

It was lovely helping you. Thank you.

Oct 4th, 2015

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Oct 4th, 2015
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Oct 4th, 2015
Oct 23rd, 2017
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