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suppose we number the multiple-choice question 1, 2, 3 and 4. If the three possible answers are labeled A, B, and C, the different responses are:

1A or 1B or 1C for the first question;

2A or 2B or 2C for the second question

and 3A or3B or 3C for the third question

and 4A or 4B or 4C for the fourth question

This makes 12 possible different answers altogether

*The easy way is to multiply 4 (the number of questions by 3 (the number of answers)

4 x 3 = 12

These are the possible answers.

115 different ways

81 different ways

108 different ways

136 different ways

82 different ways

6 different ways

Answer B 81

3 x 3 x 3 x 3 =81

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