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suppose we number the multiple-choice question 1, 2, 3 and 4. If the three possible answers are labeled A, B, and C, the different responses are:
1A or 1B or 1C for the first question;
2A or 2B or 2C for the second question
and 3A or3B or 3C for the third question
and 4A or 4B or 4C for the fourth question
This makes 12 possible different answers altogether
*The easy way is to multiply 4 (the number of questions by 3 (the number of answers)
4 x 3 = 12
These are the possible answers.
115 different ways
81 different ways
108 different ways
136 different ways
82 different ways
6 different ways
Answer B 81
3 x 3 x 3 x 3 =81
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