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The weight of the ball doesn't matter, only the height and acceleration.
vertical distance = 1/2(acceleration)t^2
6 = (1/2)(1.62)(t^2)
6 = 0.81*t^2
t^2 = 6/0.81 = 7.407
t = sqrt(7.407) = 2.72 seconds
velocity just before ball strikes the ground = (1.62 m/s^2)(2.72 s) = 4.41 m/s
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