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The weight of the ball doesn't matter, only the height and acceleration.

vertical distance = 1/2(acceleration)t^2

6 = (1/2)(1.62)(t^2)

6 = 0.81*t^2

t^2 = 6/0.81 = 7.407

t = sqrt(7.407) = 2.72 seconds

velocity just before ball strikes the ground = (1.62 m/s^2)(2.72 s) = 4.41 m/s

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