Need help in figuring out last part. Not sure how to set up equation.
At maximum speed of 70mph, a cheetah sprints for 8 minutes. How far would the cheetah travel in those 8 minutes? I got 9.28 miles in 8 min. But then the Cheetah travels at 40 mph in the 2nd 8 min? I got 4.8 miles in the 2nd 8 min. Then it says, "How much farther did the cheetah travel in the 1st 8 min. than the 2nd 8 min.? My answer was 4.48 miles, subtracting 4.8 miles from 9.28 miles. Then it says, "Was the distance traveled in the 1st 8 min. 1.75 times greater than the 2nd 8 min.~ Unsure??
the cheetah made a round-trip and took half the amount of time on the return
trip as on the front end of the trip, what would be the relationship between
the average rates on each leg of the trip? Using a complete sentence, explain
how you arrived at this conclusion.
of trip r = d/t The return trip only
took half the time which means
the rate was doubled coming
trip 2(r) = d/t
Average Rate = 2d / d / r1 + d / r2
I was not online when you accepted the bid.I thought to answer your question.Sorry for the late reply.
Average rate is not what you have indicated. It's mph of kmph.
Sentence: The cheetah went the same distance in the front end and in the return trip but the time spent for the return trip is half than the front end, for this to be true the average rate of the return trip should be twice as the average rate of the front end.
Oct 7th, 2015
I withdrew because I needed the answer sooner. I had to hand my answer in. I figured it out. It wasn't as nicely put as your answer. I hope my teacher finds it satisfactory.
Oct 8th, 2015
I will definitely try your services again on another equation that I might get stuck on. Thank you for your time.
Oct 8th, 2015
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