Hello!

The area of a sector is a corresponding part of the circle area:

A = (pi*r^2)*(a/2pi) = r^2*(a/2),

where a is the sector's angle in radians.

Therefore r^2 = 2A/a = 48/a, r = sqrt(48/a).

a) r = sqrt(48/0.7) = approx. 8,28.

b) 110 degrees is (pi/180)*100 = 5pi/9 radians,

r = sqrt[48/(5pi/9)] = approx. 5,24.

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up