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a) (y+4) = -2(x-3)
y + 2x -2 = 0
b) (y+4) = -0.5( x-3)
so the equation would be 2y + x + 5 = 0
we assume the slope of the perpendicular to be -1/m of the given line in the equation y = mx+ c
then using the slope -1/m and using the coordinate of the given point we find the equation of the new line through the point slope form.
17) the equation is: y - 5= x
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