Free Fall homework help

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A ball thrown vertically upward is caught by the thrower after 2.12 s. Find the initial velocity of the ball. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s.Find the maximum height it reaches

Oct 7th, 2015

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ball thrown from yo= o, caught at the same spot, then y= 0

t= 2.12 s.

y = y0 + v0t – ? gt2

y=0+v(2.12)- (9.8)(2.12)(2.12)

2.12=44.045212

initial velocity

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Oct 7th, 2015

initial velocity

44.o452/2.12 = 20.77

maximum height will be

time will be 2.12/2= 1.06

y = y0 + ? (v + v0)t = 0 +  ?(0 + 20.77m/s)(1.06 s) 

9.8m

Oct 7th, 2015

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