A ball thrown vertically upward is caught by the thrower after 2.12 s. Find the initial velocity of the ball. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s.Find the maximum height it reaches

Thank you for the opportunity to help you with your question!

ball thrown from yo= o, caught at the same spot, then y= 0

t= 2.12 s.

y = y_{0} + v_{0}t – ? gt^{2}

y=0+v(2.12)- (9.8)(2.12)(2.12)

2.12=44.045212

initial velocity

let submit soon pliz

44.o452/2.12 = 20.77

maximum height will be

time will be 2.12/2= 1.06

y = y_{0} + ? (v + v_{0})t = 0 + ?(0 + 20.77m/s)(1.06 s)

9.8m

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up