Calculate the force required to pull a copper ball of radius 2.00 cm upward through a fluid at the constant speed 9.00 cm/s. Take the drag force to be proportional to the speed, with proportionality constant 0.950 kg/s. Ignore the buoyant force.

Thank you for the opportunity to help you with your question!

Density of copper is 8.92 gm/cm3

m = 8.92 *4/3*pi*(2)^3 = 298 gm = 0.298 kg drag force =f = 0.950*0.09=0.0855Nweight = mg = 0.298 *9.8 = 2.9204 N Net downward force = weight + drag force F = 0.0855+2.9204 =3.0059

this force is required to pull the copper ball.

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up