Answer the questions below about the quadratic function.
g(x)= -x^2 -2x +1
a.) does the function have a minimum or maximum value? (answer would be just min or max)
b.) where does the minimum or maximum value occur?
c.) what is the functions minimum or maximum value?
Thank you for the opportunity to help you with your question!
b)it occurs when x=-2
note:the working is to help you understand why a maximum
when the slope is zero at x and second derivative at x is less than zero it becomes a maximum
g(x)=-x^2 - 2x +1
find the first derivative of the function
divide by -2 on both sides to get the value of x
find the second derivative of the function
kindly update section c on the maximum or minimum value.To get the maximum or minimum value of the function,you substitute the value of x in the original function ie
-2^2 -2*2 + 1=4-4+1
therefore the maximum value =1
kindly accept my update and feel free to ask for more clarification.Thank you
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