Thank you for the opportunity to help you with your question!

a)maximum

b)x=-3

c)min value= -6

NOTE:the working below is to help you understand how the value were arrived at.

g(x)=-3x^2 - 18x-25

find the first derivative of the function

g'(x)=-6x-18

find the value of x by equating the equation to zero

-6x-18=0

take -18 to the other side of the equation so that the equation becomes

-6x=18

divide by -6 on both side to have the value of x

x=-3

to know if the function is a max or min.you find the second derivative

g''(x)=-6

Please let me know if you need any clarification. I'm always happy to answer your questions.

Oct 8th, 2015

kindly accept my corrections on section c about the maximum or minimum value of the function.To get the maximum or minimum value of a function you substitute the value of x in the original function as follows

-3*-3^2 - (18*-3)-25

= -27- (-54)-25 when you multiply two negative value you obtain a positive value.hence

= -27+54-25

=2

there the maximum value= 2

kindly accept the correction.If you need more clarifications kindly feel free to ask.kind regards

Oct 8th, 2015

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