Hourly wage millworkers witha mean of $24.00 an hour and standard deviation of $3.00 an hour.

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What percentage of millworkers earn between $20.00 and $25.00 per hour

Oct 8th, 2015

Thank you for the opportunity to help you with your question!

First transform  20 and 25 to z-scores: z1= (20-24)/3= -4/3 =-1.3333 ; z2=( 25-24)/3= .3333

Next, Find the area under the normal curve between those two z-scores: P(-1.3333< z <.3333)=.630559-.091211=.539347 =53.93%

53.93% of mill workers earn between $20 and $25 per hour.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 8th, 2015

How did you get the area under the normal curve answer. Did you add or multiply in the (  )

Oct 9th, 2015

I used excel function: =Norm.s.dist(z,true)

P(-1.3333< z <.3333)= P(z<.3333)-P(z<-1.3333)= .630559-.091211=.539347 =53.93%

Oct 9th, 2015

What is the wage of the top 1% of millworkers? Round to two decimal places

Oct 9th, 2015

Find the z value that corresponds to probability of .99. Norm.s.inv(.99)=2.3263

z=2.3263=( x-24)/3

x=24 +3*2.3263=30.98

Answer: $30.98

Oct 9th, 2015

I need help in my statistics problem

Oct 12th, 2015

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