##### Hourly wage millworkers witha mean of \$24.00 an hour and standard deviation of \$3.00 an hour.

label Statistics
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What percentage of millworkers earn between \$20.00 and \$25.00 per hour

Oct 8th, 2015

First transform  20 and 25 to z-scores: z1= (20-24)/3= -4/3 =-1.3333 ; z2=( 25-24)/3= .3333

Next, Find the area under the normal curve between those two z-scores: P(-1.3333< z <.3333)=.630559-.091211=.539347 =53.93%

53.93% of mill workers earn between \$20 and \$25 per hour.

Oct 8th, 2015

How did you get the area under the normal curve answer. Did you add or multiply in the (  )

Oct 9th, 2015

I used excel function: =Norm.s.dist(z,true)

P(-1.3333< z <.3333)= P(z<.3333)-P(z<-1.3333)= .630559-.091211=.539347 =53.93%

Oct 9th, 2015

What is the wage of the top 1% of millworkers? Round to two decimal places

Oct 9th, 2015

Find the z value that corresponds to probability of .99. Norm.s.inv(.99)=2.3263

z=2.3263=( x-24)/3

x=24 +3*2.3263=30.98

Oct 9th, 2015

I need help in my statistics problem

Oct 12th, 2015

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Oct 8th, 2015
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Oct 8th, 2015
Sep 24th, 2017
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