My chapter 3 test is tomorrow! help!
Thank you for the opportunity to help you with your question!
25k^2 - 36y^2
= 5^2k^2 - 6^2y^2 (write 25 = 5^2 and 36 = 6^2)
= (5k)^2 - (6y)^2
= (5k+6y) (5k-6y) use formula a^2 - b^2 = (a+b)(a-b)
Hence, the factors of given equation are (5k+6y) (5k-6y)
This is the Difference of two squares correct?
Correct. I have provided the formula and explanation alongside
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