Can someone help me, How to find the derivative of a squareroot function HELP?

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Cerggl Zvaq

Mathematics

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Hi there.

The derivative of a square root is just the derivative of what is inside the square root divided by 2* the square root.

f(x) = sqrt(5x)

f`(x) =  5/2*sqrt(5x) :)

For your example:

What's inside the square root: x^2 + 5 / x + 2 

Derivative of that: x^2 + 4x - 5 / (x+2)^2

So:

[x^2+4x-5] / [2*(x+2)^2*sqrt(x^2+5/x+2)]

Please let me know if you need any clarification. I'm always happy to answer your questions.


Anonymous
Excellent resource! Really helped me get the gist of things.

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