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Call the speed of the first train v.
We know that the first train travelled v*11 in the first eleven hours plus v*3 in the last three hours
Also, we know that the diesel train is travelling at (v+55). And we know that it travelled (v+55)*3 in the three hours
Now we just need to equate the two distances:
(v+55)*3 = v*14
3v +165 = 14v
11 v = 165
v = 15 km/h
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