The enthalpy of neutralization for the reaction of a strong acid with a strong base is
Thank you for the opportunity to help you with your question!
When acid and base reacts they neutralize to form water (H2O) and release energy.
To solve this problem, you need to know this fact and do as follows -
1. Find the total number of moles of acid (HNO3) and base (KOH) by multiplying concentration with volume
so, number of moles of HNO3 = 197.6 * 0.420 moles
2. Do the same for base.
3. Which ever (acid or base) has less number of moles, consider that. Number of moles of H2O formed will be the same (as the one which has less number of moles)
4. Multiply this number of moles of water with enthalpy. This will give you the total energy released.
Thanks so much, you just forgot to mention the conversion of mL to L so that the units crossed out for the M (mol/L). Very helpful :)
You are welcome
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