##### Can someone help me how to go through this problem or how to start ?

 Chemistry Tutor: None Selected Time limit: 1 Day

A 150.0-g sample of a metal at 27.9°C is added to 150.0 g of H2O at 13.1°C. The temperature of the water rises to 15.7°C. Calculate the specific heat capacity of the metal, assuming that all the heat lost by the metal is gained by the water.

J °C−1 g−1
Oct 10th, 2015

Where H is the specific heat capacity

Solve this equation for the specific heat capacity of the metal (H_metal), then plug in the values

Oct 10th, 2015

Ok so,   150 + x + (15.7-27.9) + ( 150 * ?* (15.7- 13.1) ) = 0
What would the H of H20 be ?

Oct 10th, 2015

The specific heat of water is (4.18 J/g*degrees C)

Oct 10th, 2015

Ok thanks , oh and the beginning part of the formula is multiplication not addition

Oct 10th, 2015

Ah yeah it is apologies

Oct 10th, 2015

Oct 10th, 2015
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Ok for the ice problem it's the same calculation, but I simplified this one, just make sure to carry the negative signs properly to get the right answer.

Oct 10th, 2015

Oct 10th, 2015
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Thanks sooo much , I really appreciate it.

Oct 11th, 2015

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Oct 10th, 2015
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Oct 10th, 2015
Dec 3rd, 2016
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