Ok I found your problem, we can continue.
Just give me a moment
The mistake you made was the subscript Uxx means the second derivative of the function and not only the first
So we take one derivative, then repeating again for the next one related to x
remember f ' (x) = e^x = e^x and f'(x)= e^x^2 = 2x*e^x^2
u '(x)= t^3*(-6x/u)e^(-x^2/u)
Answer: u ''(x)= t^3*(-36x^2/u^2)e^(-x^2/u)
Is it t cube * (-36x^2/u^2)*e^(-x^2/u)
ah excuse the last answer there is a negative sign error
u ''(x)= t^3*(36x^2/u^2)e^(-x^2/u)
can you please take a picture and attach it. I confussed
because the -2x multiplies down again so the negative cancels
ok I'll draw it out again
Variable 'u' is not defined in the answer
it shouldn't be there ("u").
I drew it out and had noticed another error, the three got mixed into the multiplication while carrying terms by mistake.
Should be the answer to the question
Second derivative (Answer)
hmm, what does your textbook say?
It's attached to the x^2 as a coefficient so should carry with the term
Sir, The answer should only have variables x and t, u is not a variable its the function name. the answer should only have x and t.
I see what you mean
my best guess is you substitute in u(x,t) again in the exponential before doing the derivative
Can you please give me the answer.
We can try using this to substitute for the answer starting with some of the work before
I will check thank you.
Just organizing more so can help
If you substitute the value for u(x,t) it would get repetitive unless using the variable u, so there'd have to be something left in variable form, should be as simple as we can get without it becoming messy
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