I need help finding the % (by mass) of sample recovered as KNO 3
mass of 150 ml beaker + KNO3: 78.01 g
mass of kno 3 recovered: 10.77 g (? is this right)
and the last thing is the first question i need to figure out the calculation to.
Thank you for the opportunity to help you with your question!
I believe more information is needed to answer the question. It is incomplete as it is. But formulas are
mass of KNO3 recovered = (mass of 150 ml beaker + KNO3: 78.01 g) - mass of 150ml beaker)
% of mass recovered as KNO3
= mass of KNO3 recovered /Total mass of sample * 100%
do u know wha tthe mass of sample is? i get it...but in lab we separated sand and KHO 3
would the mass of sample be the sand???
No. It would be the sand + KNO3
The mass of sample would be the mass of sand and KNO3 you were separating
oh ok bc i was just confused whether to use sand in this since it was a differnet part of the lab but i guess i get it....
so i would add the mass of KNO 3 and the sand together and divide mass of KNO3 recovered
i got a 20 g sample of sand, now my entire answer is 2100 ? doesnt make sense???
Am glad. Feel free to reach out to me if you have other questions.
What is the mass of the beaker so that I can complete the question for you in full.
67.24 g... i just wanna make sure im doing this right.
mass of KNO3 recovered = (mass of 150 ml beaker + KNO3:) - mass of 150ml beaker)
mass of KNO3 recovered = 78.01g - 67.24 = 10.77 g
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