A satellite is in a circular orbit about the earth (ME = 5.98 x 1024 kg). The period of the satellite is 2.09 x 104 s. What is the speed at which the satellite travels?
Thank you for the opportunity to help you with your question!
First we find the radius R of the orbit:
R = cubed root of (T^2*G*Me / 4*pi^2) where T is the period
= cubed root of ((2.09x10^4)^2*6.673x10^-11*5.98x10^24 / 4*pi^2)
= 1.64x10^7 m
Then velocity is
v = sqrt(G*Me / R)
= sqrt(6.673x10^-11*5.98x10^24 / 1.64x10^7)
= 4932.75 m/s
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?