Constructing contingency tables and find probability

Statistics
Tutor: None Selected Time limit: 1 Day

A survey of families reveal that 58% eat turkey on holiday's, 44% eat ham, and 86% have turkey or ham to eat at holiday meals.

1. construct contingency table

2. What probability that a family had turkey and ham?

3. what probability that a family selected at random had ham given they had turkey at their holiday meal?

4. what probability that a family neither had ham nor turkey for their holiday meal?

5. Are having ham and having turkey disjoint events? Explain.

Oct 12th, 2015

Thank you for the opportunity to help you with your question!

Thank you for the opportunity to help you with your question!

What is the probability that a family selected at random had neither turkey nor 
ham at their holiday meal?
P(neither ham nor turkey) 
= 1 - P(ham or turkey) 
= 1 - [P(ham) + P(turkey) - P(ham andturkey)] 
= 1 - [0.44 + 0.58 - 0.16] = 1 - 0.86 = 0.14 
or using Venn Diagram at right, 14%.

 What is the probability that a family selected at random had only ham without 
having turkey at their holiday meal? 
P(ham only) = P(ham) - P(ham and turkey) = 0.44 - 0.16 = 0.28 
or using Venn Diagram above, 28%

What is the probability that a randomly selected family having turkey had ham at 
their holiday meal?
P( ham[ turkey)=0.16/0.58=0.2759

 Are having turkey and having ham disjoint events? Explain.
No, since some families (0.16) have both ham and turkey at their holiday meals.

Please let me know if you need any clarification. I'm always happy to answer your questions.Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 12th, 2015

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Oct 12th, 2015
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Oct 12th, 2015
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