##### I really need help with this question. I've been looking at it for an hour now.

 Algebra Tutor: None Selected Time limit: 1 Day

Oct 12th, 2015

Thank you for the opportunity to help you with your question!

Thank you for the opportunity to help you with your question!

Thank you for the opportunity to help you with your question!

Let the slower snail be moving at x cm/min, then the faster slow would be moving at (x+2) cm/min.

The relative speed of the two = x+x+2=(2x+2)cm/min

Total distance covered by the two in the 25 minutes will be given by:

(2x+2)cm/min * 25min =(50x+50) cm.

But the distance between the two was initially 250cm, which is the distance the two covers before meeting. This implies that:

50x+50+250 , Implying that 50x=200 and x =4

Thus:

The speed of the slower snail is 4 cm/min and

The speed of the faster snail is 6 cm/min.

Please let me know if you need any clarification. I'm always happy to answer your questions.Please let me know if you need any clarification. I'm always happy to answer your questions.Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 12th, 2015

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Oct 12th, 2015
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Oct 12th, 2015
May 29th, 2017
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