solve this quadratic equation by factoring


label Algebra
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

(3x+3)(x-6)=25x-118

Oct 12th, 2015

Thank you for the opportunity to help you with your question!

(3x+3)(x-6)=25x-118

step 1 is to expand equation on the right

(3x(x-6) + 3( x-6) =25x-118

3x^2 - 18x + 3x - 18 = 25x - 118

3x^2 - 15x - 18 = 25x - 118

Next step is to  put like terms together

3x^2 - 15x - 25x - 18+ 118 = 0

3x^2  - 40x + 100 = 0 

3x^2 - 30x-10x + 100 = 0

3x( x-10) -10( x-10) = 0

(3x-10)  (x-10) = 0

3x-10  = 0   or    x - 10 = 0

3x= 10  or x = 10

x= 10/ 3    or 10

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 12th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Oct 12th, 2015
...
Oct 12th, 2015
Nov 22nd, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer