Percent Yield in Chemistry

Chemistry
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The reaction of 5.78g of Carbon with excess O2 yields 13.45g of CO2. What is the percent yield?

Oct 12th, 2015

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C+ O2 ----------------- CO2

MOLES of carbon that reacted =

moles = mass in grams/ molar mass

5.78/ 12 = 0.4817 moles

from formula moles of carbon reacted = moles of CO2 formed

moles of CO2 expected to be formed = 0.4817

theoretical yield = moles * molar mass

= 0.4817 * 44 

=21.193 g

% yield = actual yield/ theoretical yield * 100%

actual yield = 13.45g


% yield = 13.45/ 21.193 * 100%


= 63.46%


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Oct 12th, 2015

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Oct 12th, 2015

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Oct 12th, 2015

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