Percent Yield in Chemistry

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The reaction of 5.78g of Carbon with excess O2 yields 13.45g of CO2. What is the percent yield?

Oct 12th, 2015

Thank you for the opportunity to help you with your question!


C+ O2 ----------------- CO2

MOLES of carbon that reacted =

moles = mass in grams/ molar mass

5.78/ 12 = 0.4817 moles

from formula moles of carbon reacted = moles of CO2 formed

moles of CO2 expected to be formed = 0.4817

theoretical yield = moles * molar mass

= 0.4817 * 44 

=21.193 g

% yield = actual yield/ theoretical yield * 100%

actual yield = 13.45g


% yield = 13.45/ 21.193 * 100%


= 63.46%


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Oct 12th, 2015

Thank you 

Oct 12th, 2015

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Oct 12th, 2015

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