A technician draws plans for a 400,000-gallon cylindrical tank with radius 27.0

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A technician draws plans for a

400,000-gallon
cylindrical tank with radius 27.0 ft. What should the height be? (1 ft3 = 7.48 gal. Round your answer using the rules for working with measurements.)

Oct 13th, 2015

Thank you for the opportunity to help you with your question!

Volume of a cylinder is the area of the base (r^2*pi) times the height.

V = r^2(pi)(h)

If we know that this is a 400,000 gallon tank then we can convert gallons to cubic feet.

400000/7.48=53475.9358289 (I will round at the end of calculations and if you need me to do something else I can redo it.) So the volume is 53475.9358289.

We can rearrange the volume equation to V/(r^2(pi))=h

Plugging in the numbers we have 53475.9358289/(27^2(pi)= 23.4500041 feet.  I would round the answer to 23.45

Don't be afraid to ask me any questions about my explanation.
Oct 13th, 2015

with sig figs how would that work

Oct 13th, 2015

With siginificant figures you do the rounding at the end.  Since 400,000 has 1 sig fig and 7.48 has 3 I would round the answer to 23.5

Oct 13th, 2015

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Oct 13th, 2015
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Oct 13th, 2015
Jun 24th, 2017
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