Graph the line through (6, 2) that is perpendicular to the line with equation 3x - 2y = 6.
The equation of line which is going through (6, 2) is
(y-2) = m*(x-6) for some m.
The slope of the line 3x - 2y = 6, or y = 1.5x - 3, is m1=1.5.The slope of the perpedicular line is -1/m1 = -2/3.
The answer: y-2 = (-2/3)*(x-6) = -(2/3)x + 4, or
3y + 2x = 18.
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