Probability Computations for General Normal Random Variables

label Statistics
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Oct 14th, 2015

Hi there! Thank you for the opportunity to help you with your question!

You need to compute the z score. First note that: 26 hours +18/60 hours = 26.6 hrs 

z= (26.6-25.6)/0.32 


Probability that it works is less than 0.09%


Please let me know if you need any clarification. Always glad to help!
Oct 14th, 2015

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Oct 14th, 2015
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