How do you find the axis of a symmetry on quadric functons ?

Algebra
Tutor: None Selected Time limit: 1 Day

y= -x^2+4x-6 

Oct 14th, 2015

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For a general quadratic equation, y= ax^2 + bx + c, axis of symmetry is given by the the equation, x = -b/2a

here, in the given equation, a = -1, b = 4 and c = -6

Therefore, axis of symmetry is -

x = -4/(2*(-1))

or, x = 2

Axis of symmetry divides the graph of quadratic equation in exact halves.

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Oct 14th, 2015

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