10.0-kg box starts
at rest and slides 3.5 m down a ramp inclined at an angle of 10 degrees with
the horizontal. If there is no friction between the ramp surface and crate,
what is the velocity of the crate at the bottom of the ramp?
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Vf^2 - Vi^2 = 2(gx)(dx) Vi = 0 (starts at rest) gx = component of g which acts along the surface of the ramp gx = 9.8 m/s^2(sin10 deg) = 1.70 m/s^2 Vf = √[2(gx)(dx)] Vf = √[2(1.70)(3.5)] Vf = 3.4 m/s ANS
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