We are doing proofs by contrapositive in my discrete math class. The original statement is "Suppose x is a real number. If (x^3-x)>0, then x>-1."

Thank you for the opportunity to help you with your question!

(x^3-x) > 0

x( x^2 -1) > 0

therefore

x>0 and x^2-1

if x^2-1 >1

there will be two solution

x > -1 or x >1

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up