We are doing proofs by contrapositive in my discrete math class. The original statement is "Suppose x is a real number. If (x^3-x)>0, then x>-1."
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(x^3-x) > 0
x( x^2 -1) > 0
x>0 and x^2-1
if x^2-1 >1
there will be two solution
x > -1 or x >1
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