f(x)=ax^2+bx+c has vertex at (1, 5) and passes through the point (2, 7) Find the following:

a= b= c=

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y=a(x-h)^2+k

vertex at (h, k ) = (1, 5)

y=a(x-1)^2+5

passes through the point (2, 7)

7=a(2-1)^2+5

7-5=a

a=1

y=(x-1)^2+5=x^2-2x+1+5=x^2-2x+6

so a=1 b=-2 c=6

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